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5212113 = 31737371
BaseRepresentation
bin10011111000011111010001
3100210210200020
4103320133101
52313241423
6303414053
762205444
oct23703721
910723606
105212113
112a3aa35
1218b4329
1311064ba
1499965b
156ce4e3
hex4f87d1

5212113 has 4 divisors (see below), whose sum is σ = 6949488. Its totient is φ = 3474740.

The previous prime is 5212111. The next prime is 5212133. The reversal of 5212113 is 3112125.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5212113 - 21 = 5212111 is a prime.

It is a super-2 number, since 2×52121132 = 54332243849538, which contains 22 as substring.

It is a D-number.

It is a junction number, because it is equal to n+sod(n) for n = 5212092 and 5212101.

It is not an unprimeable number, because it can be changed into a prime (5212111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 868683 + ... + 868688.

It is an arithmetic number, because the mean of its divisors is an integer number (1737372).

Almost surely, 25212113 is an apocalyptic number.

It is an amenable number.

5212113 is a deficient number, since it is larger than the sum of its proper divisors (1737375).

5212113 is a wasteful number, since it uses less digits than its factorization.

5212113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1737374.

The product of its digits is 60, while the sum is 15.

The square root of 5212113 is about 2283.0052562357. The cubic root of 5212113 is about 173.3822392407.

Adding to 5212113 its reverse (3112125), we get a palindrome (8324238).

The spelling of 5212113 in words is "five million, two hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 1737371 5212113