Base | Representation |
---|---|
bin | 10111101101001100000100… |
… | …01000100011101101001011 |
3 | 20211120121011100211011011120 |
4 | 23312212002020203231023 |
5 | 23313100123021244120 |
6 | 302512141153130323 |
7 | 13660165662234501 |
oct | 1366460210435513 |
9 | 224517140734146 |
10 | 52130201353035 |
11 | 156793266a5573 |
12 | 5a1b222b599a3 |
13 | 2311b1a79ac80 |
14 | cc31881b8671 |
15 | 60605d4c6140 |
hex | 2f6982223b4b |
52130201353035 has 32 divisors (see below), whose sum is σ = 92721906536448. Its totient is φ = 24836224959360.
The previous prime is 52130201353033. The next prime is 52130201353067. The reversal of 52130201353035 is 53035310203125.
It is not a de Polignac number, because 52130201353035 - 21 = 52130201353033 is a prime.
It is a super-2 number, since 2×521302013530352 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 52130201352987 and 52130201353005.
It is not an unprimeable number, because it can be changed into a prime (52130201353031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4311838567 + ... + 4311850656.
It is an arithmetic number, because the mean of its divisors is an integer number (2897559579264).
Almost surely, 252130201353035 is an apocalyptic number.
52130201353035 is a deficient number, since it is larger than the sum of its proper divisors (40591705183413).
52130201353035 is a wasteful number, since it uses less digits than its factorization.
52130201353035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8623689275.
The product of its (nonzero) digits is 40500, while the sum is 33.
The spelling of 52130201353035 in words is "fifty-two trillion, one hundred thirty billion, two hundred one million, three hundred fifty-three thousand, thirty-five".
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