Base | Representation |
---|---|
bin | 10111110011000111111001… |
… | …10000101000111001011101 |
3 | 20212022002111221202121211011 |
4 | 23321203330300220321131 |
5 | 23324420240232041300 |
6 | 303145544103255221 |
7 | 14011005222323131 |
oct | 1371437460507135 |
9 | 225262457677734 |
10 | 52334122143325 |
11 | 1574785a669520 |
12 | 5a5285374a511 |
13 | 23281181970a9 |
14 | cccdb0cb13c1 |
15 | 60b4e5c75eba |
hex | 2f98fcc28e5d |
52334122143325 has 48 divisors (see below), whose sum is σ = 71045676928512. Its totient is φ = 37925842680000.
The previous prime is 52334122143287. The next prime is 52334122143337.
52334122143325 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 52334122143325 - 237 = 52196683189853 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 253991794 + ... + 254197756.
It is an arithmetic number, because the mean of its divisors is an integer number (1480118269344).
Almost surely, 252334122143325 is an apocalyptic number.
52334122143325 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
52334122143325 is a deficient number, since it is larger than the sum of its proper divisors (18711554785187).
52334122143325 is a wasteful number, since it uses less digits than its factorization.
52334122143325 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 209266 (or 209261 counting only the distinct ones).
The product of its digits is 518400, while the sum is 40.
It can be divided in two parts, 5233412 and 2143325, that added together give a palindrome (7376737).
The spelling of 52334122143325 in words is "fifty-two trillion, three hundred thirty-four billion, one hundred twenty-two million, one hundred forty-three thousand, three hundred twenty-five".
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