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5259490916161 is a prime number
BaseRepresentation
bin100110010001001001000…
…0101100111011101000001
3200121210122222001110220211
41030202102011213131001
51142132414133304121
615104102103234121
71051662042104326
oct114422205473501
920553588043824
105259490916161
1117485a0564579
1270b3a8a48941
132c1c77527981
141427bc87cb4d
1591c28888ce1
hex4c892167741

5259490916161 has 2 divisors, whose sum is σ = 5259490916162. Its totient is φ = 5259490916160.

The previous prime is 5259490916159. The next prime is 5259490916167. The reversal of 5259490916161 is 1616190949525.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4660676499600 + 598814416561 = 2158860^2 + 773831^2 .

It is a cyclic number.

It is not a de Polignac number, because 5259490916161 - 21 = 5259490916159 is a prime.

It is a super-3 number, since 3×52594909161613 (a number of 39 digits) contains 333 as substring.

Together with 5259490916159, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 5259490916096 and 5259490916105.

It is not a weakly prime, because it can be changed into another prime (5259490916167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2629745458080 + 2629745458081.

It is an arithmetic number, because the mean of its divisors is an integer number (2629745458081).

Almost surely, 25259490916161 is an apocalyptic number.

It is an amenable number.

5259490916161 is a deficient number, since it is larger than the sum of its proper divisors (1).

5259490916161 is an equidigital number, since it uses as much as digits as its factorization.

5259490916161 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5248800, while the sum is 58.

The spelling of 5259490916161 in words is "five trillion, two hundred fifty-nine billion, four hundred ninety million, nine hundred sixteen thousand, one hundred sixty-one".