Base | Representation |
---|---|
bin | 100110010001001001000… |
… | …0101100111011101000111 |
3 | 200121210122222001110221001 |
4 | 1030202102011213131013 |
5 | 1142132414133304132 |
6 | 15104102103234131 |
7 | 1051662042104335 |
oct | 114422205473507 |
9 | 20553588043831 |
10 | 5259490916167 |
11 | 17485a0564584 |
12 | 70b3a8a48947 |
13 | 2c1c77527987 |
14 | 1427bc87cb55 |
15 | 91c28888ce7 |
hex | 4c892167747 |
5259490916167 has 2 divisors, whose sum is σ = 5259490916168. Its totient is φ = 5259490916166.
The previous prime is 5259490916161. The next prime is 5259490916213. The reversal of 5259490916167 is 7616190949525.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5259490916167 - 23 = 5259490916159 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5259490916099 and 5259490916108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5259490916161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2629745458083 + 2629745458084.
It is an arithmetic number, because the mean of its divisors is an integer number (2629745458084).
Almost surely, 25259490916167 is an apocalyptic number.
5259490916167 is a deficient number, since it is larger than the sum of its proper divisors (1).
5259490916167 is an equidigital number, since it uses as much as digits as its factorization.
5259490916167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36741600, while the sum is 64.
The spelling of 5259490916167 in words is "five trillion, two hundred fifty-nine billion, four hundred ninety million, nine hundred sixteen thousand, one hundred sixty-seven".
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