530113 has 4 divisors (see below), whose sum is σ = 541440. Its totient is φ = 518788.

The previous prime is 530093. The next prime is 530129. The reversal of 530113 is 311035.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311035 = 5 ⋅62207.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-530113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 530093 and 530102.

It is not an unprimeable number, because it can be changed into a prime (530143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5593 + ... + 5686.

It is an arithmetic number, because the mean of its divisors is an integer number (135360).

2⁵³⁰¹¹³ is an apocalyptic number.

It is an amenable number.

530113 is a deficient number, since it is larger than the sum of its proper divisors (11327).

530113 is a wasteful number, since it uses less digits than its factorization.

530113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11326.

The product of its (nonzero) digits is 45, while the sum is 13.

The square root of 530113 is about 728.0885935104. The cubic root of 530113 is about 80.9324743330.

Adding to 530113 its reverse (311035), we get a palindrome (841148).

The spelling of 530113 in words is "five hundred thirty thousand, one hundred thirteen".