Base | Representation |
---|---|
bin | 110001010111111101… |
… | …010101001111000111 |
3 | 12001211201122102212212 |
4 | 301113331111033013 |
5 | 1332033404144421 |
6 | 40204353534035 |
7 | 3554524432631 |
oct | 612775251707 |
9 | 161751572785 |
10 | 53015303111 |
11 | 205358359a1 |
12 | a33687431b |
13 | 4ccb681854 |
14 | 27ccd9ba51 |
15 | 15a445ce5b |
hex | c57f553c7 |
53015303111 has 4 divisors (see below), whose sum is σ = 53128826712. Its totient is φ = 52901779512.
The previous prime is 53015303083. The next prime is 53015303113. The reversal of 53015303111 is 11130351035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-53015303111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53015303113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56761100 + ... + 56762033.
It is an arithmetic number, because the mean of its divisors is an integer number (13282206678).
Almost surely, 253015303111 is an apocalyptic number.
53015303111 is a deficient number, since it is larger than the sum of its proper divisors (113523601).
53015303111 is a wasteful number, since it uses less digits than its factorization.
53015303111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113523600.
The product of its (nonzero) digits is 675, while the sum is 23.
Adding to 53015303111 its reverse (11130351035), we get a palindrome (64145654146).
The spelling of 53015303111 in words is "fifty-three billion, fifteen million, three hundred three thousand, one hundred eleven".
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