Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010111101001100000011 |
3 | 200202220210011112201110100 |
4 | 1031022120002331030003 |
5 | 1143334100340230021 |
6 | 15135541542333443 |
7 | 1055044620022440 |
oct | 115123002751403 |
9 | 20686704481410 |
10 | 5302540555011 |
11 | 17648819a73a7 |
12 | 71780212a283 |
13 | 2c604835165b |
14 | 1449040949c7 |
15 | 92de7e6c626 |
hex | 4d2980bd303 |
5302540555011 has 48 divisors (see below), whose sum is σ = 8903833286400. Its totient is φ = 2977974103104.
The previous prime is 5302540555007. The next prime is 5302540555021. The reversal of 5302540555011 is 1105550452035.
5302540555011 is a `hidden beast` number, since 5 + 3 + 0 + 2 + 540 + 55 + 50 + 11 = 666.
It is not a de Polignac number, because 5302540555011 - 22 = 5302540555007 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5302540555021) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 16031260 + ... + 16358678.
It is an arithmetic number, because the mean of its divisors is an integer number (185496526800).
Almost surely, 25302540555011 is an apocalyptic number.
5302540555011 is a deficient number, since it is larger than the sum of its proper divisors (3601292731389).
5302540555011 is a wasteful number, since it uses less digits than its factorization.
5302540555011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 331848 (or 331845 counting only the distinct ones).
The product of its (nonzero) digits is 75000, while the sum is 36.
The spelling of 5302540555011 in words is "five trillion, three hundred two billion, five hundred forty million, five hundred fifty-five thousand, eleven".
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