Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …1001110100011011011111 |
3 | 200202220210021221010101212 |
4 | 1031022120021310123133 |
5 | 1143334101320313033 |
6 | 15135542045055035 |
7 | 1055044641224636 |
oct | 115123011643337 |
9 | 20686707833355 |
10 | 5302542354143 |
11 | 1764882a16091 |
12 | 71780285747b |
13 | 2c6048831528 |
14 | 14490440251d |
15 | 92de81c5748 |
hex | 4d2982746df |
5302542354143 has 4 divisors (see below), whose sum is σ = 5304309282288. Its totient is φ = 5300775426000.
The previous prime is 5302542354139. The next prime is 5302542354169. The reversal of 5302542354143 is 3414532452035.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5302542354143 - 22 = 5302542354139 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 5302542354143.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5302542351143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 883459571 + ... + 883465572.
It is an arithmetic number, because the mean of its divisors is an integer number (1326077320572).
Almost surely, 25302542354143 is an apocalyptic number.
5302542354143 is a deficient number, since it is larger than the sum of its proper divisors (1766928145).
5302542354143 is a wasteful number, since it uses less digits than its factorization.
5302542354143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1766928144.
The product of its (nonzero) digits is 864000, while the sum is 41.
The spelling of 5302542354143 in words is "five trillion, three hundred two billion, five hundred forty-two million, three hundred fifty-four thousand, one hundred forty-three".
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