Base | Representation |
---|---|
bin | 1111011011110010011… |
… | …01000001101100000111 |
3 | 1212200211112011120210210 |
4 | 13231321031001230013 |
5 | 32142040443412320 |
6 | 1043342330450503 |
7 | 53212454216316 |
oct | 7557115015407 |
9 | 1780745146723 |
10 | 530314435335 |
11 | 1949a5745443 |
12 | 86941293a33 |
13 | 3b0156c6289 |
14 | 1b94b31c27d |
15 | dbdc16d0e0 |
hex | 7b79341b07 |
530314435335 has 32 divisors (see below), whose sum is σ = 874482174720. Its totient is φ = 274269316608.
The previous prime is 530314435333. The next prime is 530314435337. The reversal of 530314435335 is 533534413035.
It is an interprime number because it is at equal distance from previous prime (530314435333) and next prime (530314435337).
It is not a de Polignac number, because 530314435335 - 21 = 530314435333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 530314435293 and 530314435302.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (530314435333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2867874 + ... + 3047183.
It is an arithmetic number, because the mean of its divisors is an integer number (27327567960).
Almost surely, 2530314435335 is an apocalyptic number.
530314435335 is a deficient number, since it is larger than the sum of its proper divisors (344167739385).
530314435335 is a wasteful number, since it uses less digits than its factorization.
530314435335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5915247.
The product of its (nonzero) digits is 486000, while the sum is 39.
The spelling of 530314435335 in words is "five hundred thirty billion, three hundred fourteen million, four hundred thirty-five thousand, three hundred thirty-five".
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