Base | Representation |
---|---|
bin | 1111011011110100011… |
… | …00010010111110010001 |
3 | 1212200212200101020100010 |
4 | 13231322030102332101 |
5 | 32142104220134301 |
6 | 1043344122145133 |
7 | 53213045205522 |
oct | 7557214227621 |
9 | 1780780336303 |
10 | 530331021201 |
11 | 194a04043673 |
12 | 869469521a9 |
13 | 3b018c826b7 |
14 | 1b94d5d8849 |
15 | dbdd8475d6 |
hex | 7b7a312f91 |
530331021201 has 16 divisors (see below), whose sum is σ = 738091791360. Its totient is φ = 338072130000.
The previous prime is 530331021173. The next prime is 530331021211. The reversal of 530331021201 is 102120133035.
It is not a de Polignac number, because 530331021201 - 25 = 530331021169 is a prime.
It is a super-2 number, since 2×5303310212012 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (530331021211) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1035675 + ... + 1460576.
It is an arithmetic number, because the mean of its divisors is an integer number (46130736960).
Almost surely, 2530331021201 is an apocalyptic number.
It is an amenable number.
530331021201 is a deficient number, since it is larger than the sum of its proper divisors (207760770159).
530331021201 is a wasteful number, since it uses less digits than its factorization.
530331021201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2499356.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 530331021201 its reverse (102120133035), we get a palindrome (632451154236).
The spelling of 530331021201 in words is "five hundred thirty billion, three hundred thirty-one million, twenty-one thousand, two hundred one".
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