Base | Representation |
---|---|
bin | 11111100111000… |
… | …110011000010001 |
3 | 1100221221020102200 |
4 | 133213012120101 |
5 | 2041231442231 |
6 | 124343033413 |
7 | 16066562535 |
oct | 3747063021 |
9 | 1327836380 |
10 | 530343441 |
11 | 252401971 |
12 | 12973b869 |
13 | 85b4a4b4 |
14 | 50613bc5 |
15 | 3185dbe6 |
hex | 1f9c6611 |
530343441 has 24 divisors (see below), whose sum is σ = 828382464. Its totient is φ = 325680000.
The previous prime is 530343439. The next prime is 530343449. The reversal of 530343441 is 144343035.
It is not a de Polignac number, because 530343441 - 21 = 530343439 is a prime.
It is a super-3 number, since 3×5303434413 (a number of 27 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (530343449) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 29685 + ... + 44066.
It is an arithmetic number, because the mean of its divisors is an integer number (34515936).
Almost surely, 2530343441 is an apocalyptic number.
530343441 is a gapful number since it is divisible by the number (51) formed by its first and last digit.
It is an amenable number.
530343441 is a deficient number, since it is larger than the sum of its proper divisors (298039023).
530343441 is a wasteful number, since it uses less digits than its factorization.
530343441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73821 (or 73818 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 27.
The square root of 530343441 is about 23029.1867203338. The cubic root of 530343441 is about 809.4419979442.
Adding to 530343441 its reverse (144343035), we get a palindrome (674686476).
The spelling of 530343441 in words is "five hundred thirty million, three hundred forty-three thousand, four hundred forty-one".
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