Base | Representation |
---|---|
bin | 11000000111111101011010… |
… | …11000111000110110000101 |
3 | 20221211112110012102210112100 |
4 | 30003332231120320312011 |
5 | 23423133000303234212 |
6 | 304454505003142313 |
7 | 14113511460216432 |
oct | 1403765530706605 |
9 | 227745405383470 |
10 | 53050050055557 |
11 | 159a3444276345 |
12 | 5b49556514999 |
13 | 237a7a149a369 |
14 | d158c9740b89 |
15 | 61ee48334bdc |
hex | 303fad638d85 |
53050050055557 has 24 divisors (see below), whose sum is σ = 79967751364800. Its totient is φ = 33825524660928.
The previous prime is 53050050055547. The next prime is 53050050055567. The reversal of 53050050055557 is 75555005005035.
It is an interprime number because it is at equal distance from previous prime (53050050055547) and next prime (53050050055567).
It is not a de Polignac number, because 53050050055557 - 211 = 53050050053509 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53050050055547) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11219707 + ... + 15230952.
It is an arithmetic number, because the mean of its divisors is an integer number (3331989640200).
Almost surely, 253050050055557 is an apocalyptic number.
It is an amenable number.
53050050055557 is a deficient number, since it is larger than the sum of its proper divisors (26917701309243).
53050050055557 is a wasteful number, since it uses less digits than its factorization.
53050050055557 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26460377 (or 26460374 counting only the distinct ones).
The product of its (nonzero) digits is 1640625, while the sum is 45.
The spelling of 53050050055557 in words is "fifty-three trillion, fifty billion, fifty million, fifty-five thousand, five hundred fifty-seven".
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