Base | Representation |
---|---|
bin | 100110100110010110001… |
… | …1100011001000000000111 |
3 | 200210011012200100100121111 |
4 | 1031030230130121000013 |
5 | 1143404200221004003 |
6 | 15141033001225451 |
7 | 1055163411053044 |
oct | 115145434310007 |
9 | 20704180310544 |
10 | 5305030250503 |
11 | 176593a302485 |
12 | 718197a92287 |
13 | 2c63540b3759 |
14 | 144a9c9c21cb |
15 | 92ee180ee6d |
hex | 4d32c719007 |
5305030250503 has 16 divisors (see below), whose sum is σ = 5330086795264. Its totient is φ = 5280030709920.
The previous prime is 5305030250467. The next prime is 5305030250543. The reversal of 5305030250503 is 3050520305035.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5305030250503 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5305030250543) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 696103033 + ... + 696110653.
It is an arithmetic number, because the mean of its divisors is an integer number (333130424704).
Almost surely, 25305030250503 is an apocalyptic number.
5305030250503 is a deficient number, since it is larger than the sum of its proper divisors (25056544761).
5305030250503 is a wasteful number, since it uses less digits than its factorization.
5305030250503 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10942.
The product of its (nonzero) digits is 33750, while the sum is 31.
Adding to 5305030250503 its reverse (3050520305035), we get a palindrome (8355550555538).
The spelling of 5305030250503 in words is "five trillion, three hundred five billion, thirty million, two hundred fifty thousand, five hundred three".
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