Base | Representation |
---|---|
bin | 110001011010001110… |
… | …011100101000101101 |
3 | 12001221101020010120211 |
4 | 301122032130220231 |
5 | 1332123124004201 |
6 | 40212233142421 |
7 | 3555465662116 |
oct | 613216345055 |
9 | 161841203524 |
10 | 53053344301 |
11 | 205552588a1 |
12 | a34755aa11 |
13 | 5006510929 |
14 | 27d406120d |
15 | 15a7974651 |
hex | c5a39ca2d |
53053344301 has 8 divisors (see below), whose sum is σ = 56215467200. Its totient is φ = 49928205600.
The previous prime is 53053344299. The next prime is 53053344307. The reversal of 53053344301 is 10344335035.
53053344301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53053344301 - 21 = 53053344299 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53053344307) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9243096 + ... + 9248833.
It is an arithmetic number, because the mean of its divisors is an integer number (7026933400).
Almost surely, 253053344301 is an apocalyptic number.
It is an amenable number.
53053344301 is a deficient number, since it is larger than the sum of its proper divisors (3162122899).
53053344301 is a wasteful number, since it uses less digits than its factorization.
53053344301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18492099.
The product of its (nonzero) digits is 32400, while the sum is 31.
Adding to 53053344301 its reverse (10344335035), we get a palindrome (63397679336).
The spelling of 53053344301 in words is "fifty-three billion, fifty-three million, three hundred forty-four thousand, three hundred one".
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