Base | Representation |
---|---|
bin | 100110101000100001101… |
… | …0110101111100010000011 |
3 | 200210121021210101121110112 |
4 | 1031101003112233202003 |
5 | 1143443241130110222 |
6 | 15143125200221535 |
7 | 1055420361015620 |
oct | 115210326574203 |
9 | 20717253347415 |
10 | 5309709613187 |
11 | 176792071a971 |
12 | 71908300a8ab |
13 | 2c691b69a005 |
14 | 144dc425b347 |
15 | 931b752cbe2 |
hex | 4d4435af883 |
5309709613187 has 4 divisors (see below), whose sum is σ = 6068239557936. Its totient is φ = 4551179668440.
The previous prime is 5309709613181. The next prime is 5309709613193. The reversal of 5309709613187 is 7813169079035.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (5309709613181) and next prime (5309709613193).
It is a cyclic number.
It is not a de Polignac number, because 5309709613187 - 212 = 5309709609091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5309709613181) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 379264972364 + ... + 379264972377.
It is an arithmetic number, because the mean of its divisors is an integer number (1517059889484).
Almost surely, 25309709613187 is an apocalyptic number.
5309709613187 is a deficient number, since it is larger than the sum of its proper divisors (758529944749).
5309709613187 is an equidigital number, since it uses as much as digits as its factorization.
5309709613187 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 758529944748.
The product of its (nonzero) digits is 8573040, while the sum is 59.
The spelling of 5309709613187 in words is "five trillion, three hundred nine billion, seven hundred nine million, six hundred thirteen thousand, one hundred eighty-seven".
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