Base | Representation |
---|---|
bin | 110001011110010010… |
… | …001011111110111011 |
3 | 12002010010100102110011 |
4 | 301132102023332323 |
5 | 1332243041333111 |
6 | 40223104402351 |
7 | 3560253510025 |
oct | 613622137673 |
9 | 162103312404 |
10 | 53121433531 |
11 | 2058a734291 |
12 | a3663163b7 |
13 | 501766080a |
14 | 27dd107015 |
15 | 15ad924021 |
hex | c5e48bfbb |
53121433531 has 8 divisors (see below), whose sum is σ = 53437722624. Its totient is φ = 52806010920.
The previous prime is 53121433529. The next prime is 53121433571. The reversal of 53121433531 is 13533412135.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53121433531 - 21 = 53121433529 is a prime.
It is a super-2 number, since 2×531214335312 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53121433493 and 53121433502.
It is not an unprimeable number, because it can be changed into a prime (53121433571) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 93435 + ... + 339076.
It is an arithmetic number, because the mean of its divisors is an integer number (6679715328).
Almost surely, 253121433531 is an apocalyptic number.
53121433531 is a deficient number, since it is larger than the sum of its proper divisors (316289093).
53121433531 is a wasteful number, since it uses less digits than its factorization.
53121433531 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 433241.
The product of its digits is 16200, while the sum is 31.
Adding to 53121433531 its reverse (13533412135), we get a palindrome (66654845666).
The spelling of 53121433531 in words is "fifty-three billion, one hundred twenty-one million, four hundred thirty-three thousand, five hundred thirty-one".
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