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53151304033200 = 2435244292753361
BaseRepresentation
bin11000001010111010000001…
…00110001010001110110000
320222012012210202122210201110
430011131000212022032300
523431312332313030300
6305013212203233320
714124024601635432
oct1405350046121660
9228165722583643
1053151304033200
1115a323835253aa
125b650b4218840
1323871b9a1ccb9
14d1a773142652
156228c26bd550
hex30574098a3b0

53151304033200 has 60 divisors (see below), whose sum is σ = 170261343923528. Its totient is φ = 14173681075200.

The previous prime is 53151304033151. The next prime is 53151304033211. The reversal of 53151304033200 is 233040315135.

It is a tau number, because it is divible by the number of its divisors (60).

It is a super-2 number, since 2×531513040332002 (a number of 28 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 22146375481 + ... + 22146377880.

Almost surely, 253151304033200 is an apocalyptic number.

53151304033200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

53151304033200 is an abundant number, since it is smaller than the sum of its proper divisors (117110039890328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53151304033200 is a wasteful number, since it uses less digits than its factorization.

53151304033200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44292753382 (or 44292753371 counting only the distinct ones).

The product of its (nonzero) digits is 16200, while the sum is 30.

Adding to 53151304033200 its reverse (233040315135), we get a palindrome (53384344348335).

The spelling of 53151304033200 in words is "fifty-three trillion, one hundred fifty-one billion, three hundred four million, thirty-three thousand, two hundred".