Base | Representation |
---|---|
bin | 100110101101011000001… |
… | …1111011010110101101111 |
3 | 200211121012001012111001202 |
4 | 1031122300133122311233 |
5 | 1144131111404220423 |
6 | 15152011221000115 |
7 | 1056236536305260 |
oct | 115326037326557 |
9 | 20747161174052 |
10 | 5320130538863 |
11 | 1771288aa2638 |
12 | 71b0b0b5303b |
13 | 2c78bc64461a |
14 | 1456d2270967 |
15 | 935c7334728 |
hex | 4d6b07dad6f |
5320130538863 has 4 divisors (see below), whose sum is σ = 6080149187280. Its totient is φ = 4560111890448.
The previous prime is 5320130538847. The next prime is 5320130538871. The reversal of 5320130538863 is 3688350310235.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5320130538863 - 24 = 5320130538847 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320130538263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 380009324198 + ... + 380009324211.
It is an arithmetic number, because the mean of its divisors is an integer number (1520037296820).
Almost surely, 25320130538863 is an apocalyptic number.
5320130538863 is a deficient number, since it is larger than the sum of its proper divisors (760018648417).
5320130538863 is an equidigital number, since it uses as much as digits as its factorization.
5320130538863 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 760018648416.
The product of its (nonzero) digits is 1555200, while the sum is 47.
The spelling of 5320130538863 in words is "five trillion, three hundred twenty billion, one hundred thirty million, five hundred thirty-eight thousand, eight hundred sixty-three".
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