5323231415433 has 4 divisors (see below), whose sum is σ = 7097641887248. Its totient is φ = 3548820943620.

The previous prime is 5323231415419. The next prime is 5323231415503. The reversal of 5323231415433 is 3345141323235.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 5323231415433 - 2⁵ = 5323231415401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5323231415391 and 5323231415400.

It is not an unprimeable number, because it can be changed into a prime (5323231415413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 887205235903 + ... + 887205235908.

It is an arithmetic number, because the mean of its divisors is an integer number (1774410471812).

Almost surely, 2^{5323231415433} is an apocalyptic number.

It is an amenable number.

5323231415433 is a deficient number, since it is larger than the sum of its proper divisors (1774410471815).

5323231415433 is a wasteful number, since it uses less digits than its factorization.

5323231415433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1774410471814.

The product of its digits is 388800, while the sum is 39.

Adding to 5323231415433 its reverse (3345141323235), we get a palindrome (8668372738668).

The spelling of 5323231415433 in words is "five trillion, three hundred twenty-three billion, two hundred thirty-one million, four hundred fifteen thousand, four hundred thirty-three".