Base | Representation |
---|---|
bin | 100110101110110100101… |
… | …0100010100110011001111 |
3 | 200211220012011001100010201 |
4 | 1031131221110110303033 |
5 | 1144203434220244003 |
6 | 15153243031314331 |
7 | 1056406431314041 |
oct | 115355124246317 |
9 | 20756164040121 |
10 | 5323231415503 |
11 | 177262a3a3101 |
12 | 71b81751b9a7 |
13 | 2c7c94bb8681 |
14 | 145908015a91 |
15 | 937096a2b1d |
hex | 4d769514ccf |
5323231415503 has 2 divisors, whose sum is σ = 5323231415504. Its totient is φ = 5323231415502.
The previous prime is 5323231415419. The next prime is 5323231415549. The reversal of 5323231415503 is 3055141323235.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5323231415503 - 217 = 5323231284431 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5323231415603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2661615707751 + 2661615707752.
It is an arithmetic number, because the mean of its divisors is an integer number (2661615707752).
Almost surely, 25323231415503 is an apocalyptic number.
5323231415503 is a deficient number, since it is larger than the sum of its proper divisors (1).
5323231415503 is an equidigital number, since it uses as much as digits as its factorization.
5323231415503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 37.
Adding to 5323231415503 its reverse (3055141323235), we get a palindrome (8378372738738).
The spelling of 5323231415503 in words is "five trillion, three hundred twenty-three billion, two hundred thirty-one million, four hundred fifteen thousand, five hundred three".
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