Base | Representation |
---|---|
bin | 110001100111111110… |
… | …011100110100100101 |
3 | 12002112110022021022120 |
4 | 301213332130310211 |
5 | 1333111203004111 |
6 | 40251153420153 |
7 | 3564266540301 |
oct | 614776346445 |
9 | 162473267276 |
10 | 53284031781 |
11 | 206634a0802 |
12 | a3b086a659 |
13 | 5042250ab6 |
14 | 2816950d01 |
15 | 15bcd41406 |
hex | c67f9cd25 |
53284031781 has 4 divisors (see below), whose sum is σ = 71045375712. Its totient is φ = 35522687852.
The previous prime is 53284031681. The next prime is 53284031783. The reversal of 53284031781 is 18713048235.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53284031781 - 213 = 53284023589 is a prime.
It is a super-2 number, since 2×532840317812 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53284031783) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8880671961 + ... + 8880671966.
It is an arithmetic number, because the mean of its divisors is an integer number (17761343928).
Almost surely, 253284031781 is an apocalyptic number.
It is an amenable number.
53284031781 is a deficient number, since it is larger than the sum of its proper divisors (17761343931).
53284031781 is a wasteful number, since it uses less digits than its factorization.
53284031781 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17761343930.
The product of its (nonzero) digits is 161280, while the sum is 42.
The spelling of 53284031781 in words is "fifty-three billion, two hundred eighty-four million, thirty-one thousand, seven hundred eighty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •