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5341135502341 is a prime number
BaseRepresentation
bin100110110111001010001…
…1110111111110000000101
3200220121101220202012001001
41031232110132333300011
51200002121142033331
615205403410133301
71060612213454662
oct115562436776005
920817356665031
105341135502341
11177a187825591
12723193581231
132c98892a66b2
14146725bd6a69
1593e06412561
hex4db947bfc05

5341135502341 has 2 divisors, whose sum is σ = 5341135502342. Its totient is φ = 5341135502340.

The previous prime is 5341135502237. The next prime is 5341135502419. The reversal of 5341135502341 is 1432055311435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3492974102500 + 1848161399841 = 1868950^2 + 1359471^2 .

It is a cyclic number.

It is not a de Polignac number, because 5341135502341 - 215 = 5341135469573 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5341135502341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5341135500341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2670567751170 + 2670567751171.

It is an arithmetic number, because the mean of its divisors is an integer number (2670567751171).

Almost surely, 25341135502341 is an apocalyptic number.

It is an amenable number.

5341135502341 is a deficient number, since it is larger than the sum of its proper divisors (1).

5341135502341 is an equidigital number, since it uses as much as digits as its factorization.

5341135502341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 37.

The spelling of 5341135502341 in words is "five trillion, three hundred forty-one billion, one hundred thirty-five million, five hundred two thousand, three hundred forty-one".