Base | Representation |
---|---|
bin | 11000010010100000010111… |
… | …10011110011001011111011 |
3 | 21000010011202210021110001011 |
4 | 30021100023303303023323 |
5 | 24000102104310441220 |
6 | 305333153440534351 |
7 | 14151630230054323 |
oct | 1411201363631373 |
9 | 230104683243034 |
10 | 53412411421435 |
11 | 16023092874850 |
12 | 5ba78246213b7 |
13 | 23a59cc035b61 |
14 | d29262bba283 |
15 | 6295a56da65a |
hex | 30940bcf32fb |
53412411421435 has 8 divisors (see below), whose sum is σ = 69921702224496. Its totient is φ = 38845390124640.
The previous prime is 53412411421429. The next prime is 53412411421529.
53412411421435 is nontrivially palindromic in base 10.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53412411421435 - 25 = 53412411421403 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 485567376504 + ... + 485567376613.
It is an arithmetic number, because the mean of its divisors is an integer number (8740212778062).
Almost surely, 253412411421435 is an apocalyptic number.
53412411421435 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53412411421435 is a deficient number, since it is larger than the sum of its proper divisors (16509290803061).
53412411421435 is a wasteful number, since it uses less digits than its factorization.
53412411421435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 971134753133.
The product of its digits is 230400, while the sum is 40.
It can be divided in two parts, 5341241 and 1421435, that added together give a palindrome (6762676).
The spelling of 53412411421435 in words is "fifty-three trillion, four hundred twelve billion, four hundred eleven million, four hundred twenty-one thousand, four hundred thirty-five".
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