Base | Representation |
---|---|
bin | 111100110000100100100111… |
… | …1111111011010100010101101 |
3 | 2121002022002102021112121111211 |
4 | 1321201021033333122202231 |
5 | 1030022241241422044232 |
6 | 5132354540035514421 |
7 | 220400052460246213 |
oct | 17141111777324255 |
9 | 2532262367477454 |
10 | 534441302534317 |
11 | 145320313474172 |
12 | 4bb3637aa58a11 |
13 | 19c297a21038c9 |
14 | 95d9150496cb3 |
15 | 41bc0a10a3a47 |
hex | 1e6124ffda8ad |
534441302534317 has 2 divisors, whose sum is σ = 534441302534318. Its totient is φ = 534441302534316.
The previous prime is 534441302534303. The next prime is 534441302534327. The reversal of 534441302534317 is 713435203144435.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 410962336106436 + 123478966427881 = 20272206^2 + 11112109^2 .
It is a cyclic number.
It is not a de Polignac number, because 534441302534317 - 247 = 393703814178989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (534441302534327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267220651267158 + 267220651267159.
It is an arithmetic number, because the mean of its divisors is an integer number (267220651267159).
Almost surely, 2534441302534317 is an apocalyptic number.
It is an amenable number.
534441302534317 is a deficient number, since it is larger than the sum of its proper divisors (1).
534441302534317 is an equidigital number, since it uses as much as digits as its factorization.
534441302534317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7257600, while the sum is 49.
The spelling of 534441302534317 in words is "five hundred thirty-four trillion, four hundred forty-one billion, three hundred two million, five hundred thirty-four thousand, three hundred seventeen".
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