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534441302534317 is a prime number
BaseRepresentation
bin111100110000100100100111…
…1111111011010100010101101
32121002022002102021112121111211
41321201021033333122202231
51030022241241422044232
65132354540035514421
7220400052460246213
oct17141111777324255
92532262367477454
10534441302534317
11145320313474172
124bb3637aa58a11
1319c297a21038c9
1495d9150496cb3
1541bc0a10a3a47
hex1e6124ffda8ad

534441302534317 has 2 divisors, whose sum is σ = 534441302534318. Its totient is φ = 534441302534316.

The previous prime is 534441302534303. The next prime is 534441302534327. The reversal of 534441302534317 is 713435203144435.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 410962336106436 + 123478966427881 = 20272206^2 + 11112109^2 .

It is a cyclic number.

It is not a de Polignac number, because 534441302534317 - 247 = 393703814178989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (534441302534327) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 267220651267158 + 267220651267159.

It is an arithmetic number, because the mean of its divisors is an integer number (267220651267159).

Almost surely, 2534441302534317 is an apocalyptic number.

It is an amenable number.

534441302534317 is a deficient number, since it is larger than the sum of its proper divisors (1).

534441302534317 is an equidigital number, since it uses as much as digits as its factorization.

534441302534317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7257600, while the sum is 49.

The spelling of 534441302534317 in words is "five hundred thirty-four trillion, four hundred forty-one billion, three hundred two million, five hundred thirty-four thousand, three hundred seventeen".