Base | Representation |
---|---|
bin | 111100110000100100100111… |
… | …1111111011010100010110011 |
3 | 2121002022002102021112121112001 |
4 | 1321201021033333122202303 |
5 | 1030022241241422044243 |
6 | 5132354540035514431 |
7 | 220400052460246222 |
oct | 17141111777324263 |
9 | 2532262367477461 |
10 | 534441302534323 |
11 | 145320313474178 |
12 | 4bb3637aa58a17 |
13 | 19c297a2103902 |
14 | 95d9150496cb9 |
15 | 41bc0a10a3a4d |
hex | 1e6124ffda8b3 |
534441302534323 has 4 divisors (see below), whose sum is σ = 534537200853648. Its totient is φ = 534345404215000.
The previous prime is 534441302534317. The next prime is 534441302534327. The reversal of 534441302534323 is 323435203144435.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 534441302534323 - 217 = 534441302403251 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (534441302534327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47949151303 + ... + 47949162448.
It is an arithmetic number, because the mean of its divisors is an integer number (133634300213412).
Almost surely, 2534441302534323 is an apocalyptic number.
534441302534323 is a deficient number, since it is larger than the sum of its proper divisors (95898319325).
534441302534323 is an equidigital number, since it uses as much as digits as its factorization.
534441302534323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95898319324.
The product of its (nonzero) digits is 6220800, while the sum is 46.
Adding to 534441302534323 its reverse (323435203144435), we get a palindrome (857876505678758).
The spelling of 534441302534323 in words is "five hundred thirty-four trillion, four hundred forty-one billion, three hundred two million, five hundred thirty-four thousand, three hundred twenty-three".
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