Base | Representation |
---|---|
bin | 100110111011100001011… |
… | …0111001111100100001011 |
3 | 200221111120210101001210122 |
4 | 1031313002313033210023 |
5 | 1200130312401420344 |
6 | 15213553135533455 |
7 | 1061363315510666 |
oct | 115670267174413 |
9 | 20844523331718 |
10 | 5350503545099 |
11 | 1783154844789 |
12 | 724b6898a28b |
13 | 2ca72008946b |
14 | 146d740546dd |
15 | 942a3a8daee |
hex | 4ddc2dcf90b |
5350503545099 has 2 divisors, whose sum is σ = 5350503545100. Its totient is φ = 5350503545098.
The previous prime is 5350503545087. The next prime is 5350503545141. The reversal of 5350503545099 is 9905453050535.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5350503545099 - 212 = 5350503541003 is a prime.
It is a super-2 number, since 2×53505035450992 (a number of 26 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5350503545099.
It is not a weakly prime, because it can be changed into another prime (5350503545029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2675251772549 + 2675251772550.
It is an arithmetic number, because the mean of its divisors is an integer number (2675251772550).
Almost surely, 25350503545099 is an apocalyptic number.
5350503545099 is a deficient number, since it is larger than the sum of its proper divisors (1).
5350503545099 is an equidigital number, since it uses as much as digits as its factorization.
5350503545099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9112500, while the sum is 53.
The spelling of 5350503545099 in words is "five trillion, three hundred fifty billion, five hundred three million, five hundred forty-five thousand, ninety-nine".
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