Base | Representation |
---|---|
bin | 111100111110111010010100… |
… | …0000110011001001100111111 |
3 | 2121100021111012012021102110002 |
4 | 1321331310220012121030333 |
5 | 1030302033310423422223 |
6 | 5140504140452304515 |
7 | 220662326664125312 |
oct | 17175645006311477 |
9 | 2540244165242402 |
10 | 536412023264063 |
11 | 145a10074999941 |
12 | 501b42b131213b |
13 | 1a04058a6bc89b |
14 | 96666a2510979 |
15 | 4203493871e28 |
hex | 1e7dd2819933f |
536412023264063 has 2 divisors, whose sum is σ = 536412023264064. Its totient is φ = 536412023264062.
The previous prime is 536412023264011. The next prime is 536412023264069. The reversal of 536412023264063 is 360462320214635.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 536412023264063 - 214 = 536412023247679 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 536412023263999 and 536412023264017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (536412023264069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 268206011632031 + 268206011632032.
It is an arithmetic number, because the mean of its divisors is an integer number (268206011632032).
Almost surely, 2536412023264063 is an apocalyptic number.
536412023264063 is a deficient number, since it is larger than the sum of its proper divisors (1).
536412023264063 is an equidigital number, since it uses as much as digits as its factorization.
536412023264063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 47.
Adding to 536412023264063 its reverse (360462320214635), we get a palindrome (896874343478698).
The spelling of 536412023264063 in words is "five hundred thirty-six trillion, four hundred twelve billion, twenty-three million, two hundred sixty-four thousand, sixty-three".
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