Search a number
-
+
53715131647 is a prime number
BaseRepresentation
bin110010000001101010…
…111101110011111111
312010122111111102011021
4302001222331303333
51340002033203042
640402033405011
73611053041232
oct620152756377
9163574442137
1053715131647
1120864878491
12a4b1109767
1350b0660b88
142857ccd419
1515e5ae9867
hexc81abdcff

53715131647 has 2 divisors, whose sum is σ = 53715131648. Its totient is φ = 53715131646.

The previous prime is 53715131609. The next prime is 53715131689. The reversal of 53715131647 is 74613151735.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-53715131647 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (53715131147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857565823 + 26857565824.

It is an arithmetic number, because the mean of its divisors is an integer number (26857565824).

Almost surely, 253715131647 is an apocalyptic number.

53715131647 is a deficient number, since it is larger than the sum of its proper divisors (1).

53715131647 is an equidigital number, since it uses as much as digits as its factorization.

53715131647 is an evil number, because the sum of its binary digits is even.

The product of its digits is 264600, while the sum is 43.

The spelling of 53715131647 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-one thousand, six hundred forty-seven".