Base | Representation |
---|---|
bin | 110010000001101010… |
… | …111110110001110001 |
3 | 12010122111111121120201 |
4 | 302001222332301301 |
5 | 1340002033314401 |
6 | 40402033435201 |
7 | 3611053055611 |
oct | 620152766161 |
9 | 163574447521 |
10 | 53715135601 |
11 | 20864880456 |
12 | a4b110bb01 |
13 | 50b066290a |
14 | 2857cd0a41 |
15 | 15e5aeab01 |
hex | c81abec71 |
53715135601 has 2 divisors, whose sum is σ = 53715135602. Its totient is φ = 53715135600.
The previous prime is 53715135587. The next prime is 53715135631. The reversal of 53715135601 is 10653151735.
53715135601 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52221390400 + 1493745201 = 228520^2 + 38649^2 .
It is a cyclic number.
It is not a de Polignac number, because 53715135601 - 225 = 53681581169 is a prime.
It is not a weakly prime, because it can be changed into another prime (53715135631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26857567800 + 26857567801.
It is an arithmetic number, because the mean of its divisors is an integer number (26857567801).
Almost surely, 253715135601 is an apocalyptic number.
It is an amenable number.
53715135601 is a deficient number, since it is larger than the sum of its proper divisors (1).
53715135601 is an equidigital number, since it uses as much as digits as its factorization.
53715135601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47250, while the sum is 37.
The spelling of 53715135601 in words is "fifty-three billion, seven hundred fifteen million, one hundred thirty-five thousand, six hundred one".
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