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54001171881049 is a prime number
BaseRepresentation
bin11000100011101001000001…
…01010101101110001011001
321002012110110111221200122211
430101310200222231301121
524034223400000143144
6310503443524515121
714242312244310121
oct1421644052556131
9232173414850584
1054001171881049
111622a84a7a0298
12608195724baa1
13241939a249143
14d49956437c81
15639a6394e034
hex311d20aadc59

54001171881049 has 2 divisors, whose sum is σ = 54001171881050. Its totient is φ = 54001171881048.

The previous prime is 54001171880959. The next prime is 54001171881053. The reversal of 54001171881049 is 94018817110045.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36762333608025 + 17238838273024 = 6063195^2 + 4151968^2 .

It is a cyclic number.

It is not a de Polignac number, because 54001171881049 - 27 = 54001171880921 is a prime.

It is a super-2 number, since 2×540011718810492 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 54001171880993 and 54001171881011.

It is not a weakly prime, because it can be changed into another prime (54001171821049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27000585940524 + 27000585940525.

It is an arithmetic number, because the mean of its divisors is an integer number (27000585940525).

Almost surely, 254001171881049 is an apocalyptic number.

It is an amenable number.

54001171881049 is a deficient number, since it is larger than the sum of its proper divisors (1).

54001171881049 is an equidigital number, since it uses as much as digits as its factorization.

54001171881049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 322560, while the sum is 49.

The spelling of 54001171881049 in words is "fifty-four trillion, one billion, one hundred seventy-one million, eight hundred eighty-one thousand, forty-nine".