5403 has 4 divisors (see below), whose sum is σ = 7208. Its totient is φ = 3600.

The previous prime is 5399. The next prime is 5407. The reversal of 5403 is 3045.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (5399) and next prime (5407).

It is not a de Polignac number, because 5403 - 2² = 5399 is a prime.

It is a D-number.

It is the 74-th Hogben number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5407) by changing a digit.

It is a nontrivial repunit in base 73.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 898 + ... + 903.

It is an arithmetic number, because the mean of its divisors is an integer number (1802).

5403 is a deficient number, since it is larger than the sum of its proper divisors (1805).

5403 is a wasteful number, since it uses less digits than its factorization.

5403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1804.

The product of its (nonzero) digits is 60, while the sum is 12.

The square root of 5403 is about 73.5051018637. The cubic root of 5403 is about 17.5473547364.

Adding to 5403 its reverse (3045), we get a palindrome (8448).

The spelling of 5403 in words is "five thousand, four hundred three".