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542604831449 is a prime number
BaseRepresentation
bin1111110010101011100…
…01001010101011011001
31220212120001201101201212
413321111301022223121
532342223314101244
61053134052352505
754126152653052
oct7712561125331
91825501641655
10542604831449
1119a1323109aa
12891b1315735
133c223a75405
141c39572d729
15e1ab151d9e
hex7e55c4aad9

542604831449 has 2 divisors, whose sum is σ = 542604831450. Its totient is φ = 542604831448.

The previous prime is 542604831311. The next prime is 542604831463. The reversal of 542604831449 is 944138406245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 451137902224 + 91466929225 = 671668^2 + 302435^2 .

It is a cyclic number.

It is not a de Polignac number, because 542604831449 - 224 = 542588054233 is a prime.

It is a super-2 number, since 2×5426048314492 (a number of 24 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 542604831397 and 542604831406.

It is not a weakly prime, because it can be changed into another prime (542604831149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271302415724 + 271302415725.

It is an arithmetic number, because the mean of its divisors is an integer number (271302415725).

Almost surely, 2542604831449 is an apocalyptic number.

It is an amenable number.

542604831449 is a deficient number, since it is larger than the sum of its proper divisors (1).

542604831449 is an equidigital number, since it uses as much as digits as its factorization.

542604831449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3317760, while the sum is 50.

The spelling of 542604831449 in words is "five hundred forty-two billion, six hundred four million, eight hundred thirty-one thousand, four hundred forty-nine".