Base | Representation |
---|---|
bin | 1111110011101010100… |
… | …01111011100110010011 |
3 | 1220220220220112021000221 |
4 | 13321311101323212103 |
5 | 32344314134423011 |
6 | 1053302340053511 |
7 | 54145232461015 |
oct | 7716521734623 |
9 | 1826826467027 |
10 | 543133514131 |
11 | 19a38378903a |
12 | 8931a394297 |
13 | 3c2a94609c0 |
14 | 1c405a301b5 |
15 | e1dc783971 |
hex | 7e7547b993 |
543133514131 has 16 divisors (see below), whose sum is σ = 619371192384. Its totient is φ = 471823340544.
The previous prime is 543133514129. The next prime is 543133514137. The reversal of 543133514131 is 131415331345.
It is a cyclic number.
It is not a de Polignac number, because 543133514131 - 21 = 543133514129 is a prime.
It is a super-2 number, since 2×5431335141312 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (543133514137) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2738055 + ... + 2929711.
It is an arithmetic number, because the mean of its divisors is an integer number (38710699524).
Almost surely, 2543133514131 is an apocalyptic number.
543133514131 is a deficient number, since it is larger than the sum of its proper divisors (76237678253).
543133514131 is a wasteful number, since it uses less digits than its factorization.
543133514131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204510.
The product of its digits is 32400, while the sum is 34.
Adding to 543133514131 its reverse (131415331345), we get a palindrome (674548845476).
The spelling of 543133514131 in words is "five hundred forty-three billion, one hundred thirty-three million, five hundred fourteen thousand, one hundred thirty-one".
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