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544424120131 = 1732024948243
BaseRepresentation
bin1111110110000100011…
…01001100111101000011
31221001020212000211122011
413323002031030331003
532404440033321011
61054034402153351
754222223444513
oct7730215147503
91831225024564
10544424120131
1119a98624a471
128961a652857
133c453959ba8
141c4c91c7843
15e265c1a621
hex7ec234cf43

544424120131 has 4 divisors (see below), whose sum is σ = 576449068392. Its totient is φ = 512399171872.

The previous prime is 544424120117. The next prime is 544424120153. The reversal of 544424120131 is 131021424445.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 544424120131 - 221 = 544422022979 is a prime.

It is a super-2 number, since 2×5444241201312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 544424120093 and 544424120102.

It is not an unprimeable number, because it can be changed into a prime (544424120101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16012474105 + ... + 16012474138.

It is an arithmetic number, because the mean of its divisors is an integer number (144112267098).

Almost surely, 2544424120131 is an apocalyptic number.

544424120131 is a deficient number, since it is larger than the sum of its proper divisors (32024948261).

544424120131 is a wasteful number, since it uses less digits than its factorization.

544424120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32024948260.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 544424120131 its reverse (131021424445), we get a palindrome (675445544576).

The spelling of 544424120131 in words is "five hundred forty-four billion, four hundred twenty-four million, one hundred twenty thousand, one hundred thirty-one".

Divisors: 1 17 32024948243 544424120131