Base | Representation |
---|---|
bin | 11000111100100001111000… |
… | …11100100001110011101111 |
3 | 21012020012210101220011022221 |
4 | 30132100330130201303233 |
5 | 24142231234110302413 |
6 | 312400353020420211 |
7 | 14361145104030064 |
oct | 1436207434416357 |
9 | 235205711804287 |
10 | 54856336415983 |
11 | 1652a494894623 |
12 | 619b6380a7667 |
13 | 247bc12c11a5b |
14 | d790bcd80c6b |
15 | 651e14bdd68d |
hex | 31e43c721cef |
54856336415983 has 2 divisors, whose sum is σ = 54856336415984. Its totient is φ = 54856336415982.
The previous prime is 54856336415981. The next prime is 54856336416031. The reversal of 54856336415983 is 38951463365845.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54856336415983 - 21 = 54856336415981 is a prime.
Together with 54856336415981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (54856336415981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27428168207991 + 27428168207992.
It is an arithmetic number, because the mean of its divisors is an integer number (27428168207992).
Almost surely, 254856336415983 is an apocalyptic number.
54856336415983 is a deficient number, since it is larger than the sum of its proper divisors (1).
54856336415983 is an equidigital number, since it uses as much as digits as its factorization.
54856336415983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1119744000, while the sum is 70.
The spelling of 54856336415983 in words is "fifty-four trillion, eight hundred fifty-six billion, three hundred thirty-six million, four hundred fifteen thousand, nine hundred eighty-three".
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