Base | Representation |
---|---|
bin | 1010010100100000… |
… | …10001101000011011 |
3 | 112022010220011002121 |
4 | 11022100101220123 |
5 | 42321412412203 |
6 | 2313445242111 |
7 | 254206402453 |
oct | 51220215033 |
9 | 15263804077 |
10 | 5540747803 |
11 | 2393675918 |
12 | 10a7703337 |
13 | 6a3bac9c6 |
14 | 3a7c22d63 |
15 | 22666d0bd |
hex | 14a411a1b |
5540747803 has 2 divisors, whose sum is σ = 5540747804. Its totient is φ = 5540747802.
The previous prime is 5540747711. The next prime is 5540747809. The reversal of 5540747803 is 3087470455.
5540747803 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5540747803 - 29 = 5540747291 is a prime.
It is a super-3 number, since 3×55407478033 (a number of 30 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 5540747803.
It is not a weakly prime, because it can be changed into another prime (5540747809) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2770373901 + 2770373902.
It is an arithmetic number, because the mean of its divisors is an integer number (2770373902).
Almost surely, 25540747803 is an apocalyptic number.
5540747803 is a deficient number, since it is larger than the sum of its proper divisors (1).
5540747803 is an equidigital number, since it uses as much as digits as its factorization.
5540747803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 470400, while the sum is 43.
The square root of 5540747803 is about 74436.1995469946. The cubic root of 5540747803 is about 1769.5226566642.
The spelling of 5540747803 in words is "five billion, five hundred forty million, seven hundred forty-seven thousand, eight hundred three".
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