Base | Representation |
---|---|
bin | 111111000000100001101101… |
… | …1011010100101001111101011 |
3 | 2200200100111212001112002021222 |
4 | 1332001003123122211033223 |
5 | 1040120420340312220233 |
6 | 5242424010204452255 |
7 | 224511345261004115 |
oct | 17601033332451753 |
9 | 2620314761462258 |
10 | 554226261054443 |
11 | 1506590457975aa |
12 | 521b091954a08b |
13 | 1aa33409a88113 |
14 | 9ac09a0ad23b5 |
15 | 4411a6c20a898 |
hex | 1f810db6a53eb |
554226261054443 has 2 divisors, whose sum is σ = 554226261054444. Its totient is φ = 554226261054442.
The previous prime is 554226261054413. The next prime is 554226261054457. The reversal of 554226261054443 is 344450162622455.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 554226261054443 - 28 = 554226261054187 is a prime.
It is not a weakly prime, because it can be changed into another prime (554226261054413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 277113130527221 + 277113130527222.
It is an arithmetic number, because the mean of its divisors is an integer number (277113130527222).
Almost surely, 2554226261054443 is an apocalyptic number.
554226261054443 is a deficient number, since it is larger than the sum of its proper divisors (1).
554226261054443 is an equidigital number, since it uses as much as digits as its factorization.
554226261054443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648000, while the sum is 53.
The spelling of 554226261054443 in words is "five hundred fifty-four trillion, two hundred twenty-six billion, two hundred sixty-one million, fifty-four thousand, four hundred forty-three".
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