Base | Representation |
---|---|
bin | 11001010010100000001000… |
… | …11101001100101100100111 |
3 | 21021220101111220100121120222 |
4 | 30221100010131030230213 |
5 | 24242113431143433110 |
6 | 314135252252514555 |
7 | 14466533064535301 |
oct | 1451200435145447 |
9 | 237811456317528 |
10 | 55611311311655 |
11 | 167a06964a6aa0 |
12 | 62a1a1777ba5b |
13 | 250517c9ca758 |
14 | da385d5c0971 |
15 | 6668a0283c55 |
hex | 32940474cb27 |
55611311311655 has 16 divisors (see below), whose sum is σ = 72800927375904. Its totient is φ = 40444220436480.
The previous prime is 55611311311651. The next prime is 55611311311669.
55611311311655 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 55611311311655 - 22 = 55611311311651 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (55611311311651) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1526687 + ... + 10656143.
It is an arithmetic number, because the mean of its divisors is an integer number (4550057960994).
Almost surely, 255611311311655 is an apocalyptic number.
55611311311655 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
55611311311655 is a deficient number, since it is larger than the sum of its proper divisors (17189616064249).
55611311311655 is a wasteful number, since it uses less digits than its factorization.
55611311311655 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9240226.
The product of its digits is 202500, while the sum is 44.
It can be divided in two parts, 5561131 and 1311655, that added together give a palindrome (6872786).
The spelling of 55611311311655 in words is "fifty-five trillion, six hundred eleven billion, three hundred eleven million, three hundred eleven thousand, six hundred fifty-five".
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