Base | Representation |
---|---|

bin | 101000100100100000100… |

… | …0110000011000000000111 |

3 | 201202001112012211002110022 |

4 | 1101021001012003000013 |

5 | 1212324031132420112 |

6 | 15505321022445355 |

7 | 1113564323022062 |

oct | 121110106030007 |

9 | 21661465732408 |

10 | 5575959654407 |

11 | 185a82995064a |

12 | 7607a973385b |

13 | 315a7026a4bc |

14 | 153c40ccb8d9 |

15 | 9a09bc7dd72 |

hex | 51241183007 |

5575959654407 has 2 divisors, whose sum is σ = 5575959654408. Its totient is φ = 5575959654406.

The previous prime is 5575959654379. The next prime is 5575959654451. The reversal of 5575959654407 is 7044569595755.

5575959654407 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5575959654407 - 2^{12} = 5575959650311 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5575959654467) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2787979827203 + 2787979827204.

It is an arithmetic number, because the mean of its divisors is an integer number (2787979827204).

Almost surely, 2^{5575959654407} is an apocalyptic number.

5575959654407 is a deficient number, since it is larger than the sum of its proper divisors (1).

5575959654407 is an equidigital number, since it uses as much as digits as its factorization.

5575959654407 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1190700000, while the sum is 71.

The spelling of 5575959654407 in words is "five trillion, five hundred seventy-five billion, nine hundred fifty-nine million, six hundred fifty-four thousand, four hundred seven".

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