Base | Representation |
---|---|
bin | 11001101010000110000110… |
… | …00100000011110110010011 |
3 | 21101202212221121120021211121 |
4 | 30311003003010003312103 |
5 | 24343404140013143330 |
6 | 315555520400223111 |
7 | 14612231561430514 |
oct | 1465030304036623 |
9 | 241685847507747 |
10 | 56421963021715 |
11 | 16a83469232155 |
12 | 63b2b5530aa97 |
13 | 2563750696a35 |
14 | dd0ba2472a0b |
15 | 67c9e876817a |
hex | 3350c3103d93 |
56421963021715 has 4 divisors (see below), whose sum is σ = 67706355626064. Its totient is φ = 45137570417368.
The previous prime is 56421963021703. The next prime is 56421963021727. The reversal of 56421963021715 is 51712036912465.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (56421963021703) and next prime (56421963021727).
It is a cyclic number.
It is not a de Polignac number, because 56421963021715 - 213 = 56421963013523 is a prime.
It is a super-2 number, since 2×564219630217152 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5642196302167 + ... + 5642196302176.
It is an arithmetic number, because the mean of its divisors is an integer number (16926588906516).
Almost surely, 256421963021715 is an apocalyptic number.
56421963021715 is a deficient number, since it is larger than the sum of its proper divisors (11284392604349).
56421963021715 is a wasteful number, since it uses less digits than its factorization.
56421963021715 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11284392604348.
The product of its (nonzero) digits is 2721600, while the sum is 52.
The spelling of 56421963021715 in words is "fifty-six trillion, four hundred twenty-one billion, nine hundred sixty-three million, twenty-one thousand, seven hundred fifteen".
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