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57516112121981 is a prime number
BaseRepresentation
bin11010001001111100000110…
…11011101001000001111101
321112122111010202010120000012
431010332003123221001331
530014320444200400411
6322154312004513005
715054254606351402
oct1504760333510175
9245574122116005
1057516112121981
111736549a93a617
12654b0116ab765
13261299124b756
14102bb1a8602a9
1569b1d573418b
hex344f836e907d

57516112121981 has 2 divisors, whose sum is σ = 57516112121982. Its totient is φ = 57516112121980.

The previous prime is 57516112121873. The next prime is 57516112122011. The reversal of 57516112121981 is 18912121161575.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 55180383722500 + 2335728399481 = 7428350^2 + 1528309^2 .

It is a cyclic number.

It is not a de Polignac number, because 57516112121981 - 218 = 57516111859837 is a prime.

It is a super-2 number, since 2×575161121219812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (57516112121381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28758056060990 + 28758056060991.

It is an arithmetic number, because the mean of its divisors is an integer number (28758056060991).

Almost surely, 257516112121981 is an apocalyptic number.

It is an amenable number.

57516112121981 is a deficient number, since it is larger than the sum of its proper divisors (1).

57516112121981 is an equidigital number, since it uses as much as digits as its factorization.

57516112121981 is an evil number, because the sum of its binary digits is even.

The product of its digits is 302400, while the sum is 50.

The spelling of 57516112121981 in words is "fifty-seven trillion, five hundred sixteen billion, one hundred twelve million, one hundred twenty-one thousand, nine hundred eighty-one".