Search a number
-
+
5948926028317 is a prime number
BaseRepresentation
bin101011010010001011110…
…0111110110101000011101
3210001201012212211222002101
41112210113213312220131
51234431400030401232
620352522054325101
71152536634626506
oct126442747665035
923051185758071
105948926028317
111993a1a7225a8
12800b37359791
13341c9ac5368c
14167d029b7bad
15a4b2a19e1e7
hex569179f6a1d

5948926028317 has 2 divisors, whose sum is σ = 5948926028318. Its totient is φ = 5948926028316.

The previous prime is 5948926028141. The next prime is 5948926028329. The reversal of 5948926028317 is 7138206298495.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5134638168676 + 814287859641 = 2265974^2 + 902379^2 .

It is a cyclic number.

It is not a de Polignac number, because 5948926028317 - 211 = 5948926026269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5948926038317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2974463014158 + 2974463014159.

It is an arithmetic number, because the mean of its divisors is an integer number (2974463014159).

It is a 2-persistent number, because it is pandigital, and so is 2⋅5948926028317 = 11897852056634, but 3⋅5948926028317 = 17846778084951 is not.

Almost surely, 25948926028317 is an apocalyptic number.

It is an amenable number.

5948926028317 is a deficient number, since it is larger than the sum of its proper divisors (1).

5948926028317 is an equidigital number, since it uses as much as digits as its factorization.

5948926028317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 52254720, while the sum is 64.

The spelling of 5948926028317 in words is "five trillion, nine hundred forty-eight billion, nine hundred twenty-six million, twenty-eight thousand, three hundred seventeen".