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612482680493 = 913696703397
BaseRepresentation
bin10001110100110101101…
…00000000011010101101
32011112220222012220222222
420322122310000122231
540013331031233433
61145212021245125
762151614612345
oct10723264003255
92145828186888
10612482680493
11216830562172
129a8532637a5
13459abac1a98
1421904029d25
1510deab84b98
hex8e9ad006ad

612482680493 has 4 divisors (see below), whose sum is σ = 612489475260. Its totient is φ = 612475885728.

The previous prime is 612482680489. The next prime is 612482680529. The reversal of 612482680493 is 394086284216.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 354665509444 + 257817171049 = 595538^2 + 507757^2 .

It is a cyclic number.

It is not a de Polignac number, because 612482680493 - 22 = 612482680489 is a prime.

It is a super-3 number, since 3×6124826804933 (a number of 36 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (612482680423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3260330 + ... + 3443067.

It is an arithmetic number, because the mean of its divisors is an integer number (153122368815).

Almost surely, 2612482680493 is an apocalyptic number.

It is an amenable number.

612482680493 is a deficient number, since it is larger than the sum of its proper divisors (6794767).

612482680493 is an equidigital number, since it uses as much as digits as its factorization.

612482680493 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6794766.

The product of its (nonzero) digits is 3981312, while the sum is 53.

The spelling of 612482680493 in words is "six hundred twelve billion, four hundred eighty-two million, six hundred eighty thousand, four hundred ninety-three".

Divisors: 1 91369 6703397 612482680493