Base | Representation |
---|---|
bin | 101100101000000000101… |
… | …1110101100001110000011 |
3 | 210201022221220120101221022 |
4 | 1121100001132230032003 |
5 | 1300441332424340342 |
6 | 21013323134220055 |
7 | 1202053233600431 |
oct | 131200136541603 |
9 | 23638856511838 |
10 | 6133238121347 |
11 | 1a55101032027 |
12 | 8307b505462b |
13 | 35649205c85c |
14 | 172bc9367d51 |
15 | a98162299d2 |
hex | 594017ac383 |
6133238121347 has 2 divisors, whose sum is σ = 6133238121348. Its totient is φ = 6133238121346.
The previous prime is 6133238121317. The next prime is 6133238121349. The reversal of 6133238121347 is 7431218323316.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6133238121347 is a prime.
Together with 6133238121349, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 6133238121298 and 6133238121307.
It is not a weakly prime, because it can be changed into another prime (6133238121349) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3066619060673 + 3066619060674.
It is an arithmetic number, because the mean of its divisors is an integer number (3066619060674).
Almost surely, 26133238121347 is an apocalyptic number.
6133238121347 is a deficient number, since it is larger than the sum of its proper divisors (1).
6133238121347 is an equidigital number, since it uses as much as digits as its factorization.
6133238121347 is an evil number, because the sum of its binary digits is even.
The product of its digits is 435456, while the sum is 44.
The spelling of 6133238121347 in words is "six trillion, one hundred thirty-three billion, two hundred thirty-eight million, one hundred twenty-one thousand, three hundred forty-seven".
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