Base | Representation |
---|---|
bin | 11011111100011100011110… |
… | …01110110000111010110011 |
3 | 22001120121111000021000110012 |
4 | 31332032033032300322303 |
5 | 31023301111012204042 |
6 | 334405545305525135 |
7 | 15641436451461002 |
oct | 1576161716607263 |
9 | 261517430230405 |
10 | 61450500116147 |
11 | 1864201333907a |
12 | 6a856281a37ab |
13 | 28399aca1ac9c |
14 | 1126311c58c39 |
15 | 718706444e82 |
hex | 37e38f3b0eb3 |
61450500116147 has 2 divisors, whose sum is σ = 61450500116148. Its totient is φ = 61450500116146.
The previous prime is 61450500116111. The next prime is 61450500116171. The reversal of 61450500116147 is 74161100505416.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 61450500116147 - 224 = 61450483338931 is a prime.
It is not a weakly prime, because it can be changed into another prime (61450500106147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30725250058073 + 30725250058074.
It is an arithmetic number, because the mean of its divisors is an integer number (30725250058074).
Almost surely, 261450500116147 is an apocalyptic number.
61450500116147 is a deficient number, since it is larger than the sum of its proper divisors (1).
61450500116147 is an equidigital number, since it uses as much as digits as its factorization.
61450500116147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 41.
The spelling of 61450500116147 in words is "sixty-one trillion, four hundred fifty billion, five hundred million, one hundred sixteen thousand, one hundred forty-seven".
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