Base | Representation |
---|---|
bin | 111011101110000101… |
… | …011011001000000111 |
3 | 20010111220111201210222 |
4 | 323232011123020013 |
5 | 2022311212111013 |
6 | 45242542334555 |
7 | 4430023336265 |
oct | 735605331007 |
9 | 203456451728 |
10 | 64123941383 |
11 | 25216325287 |
12 | 10516b8a45b |
13 | 607bc557a8 |
14 | 316446b435 |
15 | 1a0480b508 |
hex | eee15b207 |
64123941383 has 4 divisors (see below), whose sum is σ = 64197059640. Its totient is φ = 64050823128.
The previous prime is 64123941361. The next prime is 64123941403. The reversal of 64123941383 is 38314932146.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 64123941383 - 210 = 64123940359 is a prime.
It is a super-2 number, since 2×641239413832 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (64123941353) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36557813 + ... + 36559566.
It is an arithmetic number, because the mean of its divisors is an integer number (16049264910).
Almost surely, 264123941383 is an apocalyptic number.
64123941383 is a deficient number, since it is larger than the sum of its proper divisors (73118257).
64123941383 is an equidigital number, since it uses as much as digits as its factorization.
64123941383 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73118256.
The product of its digits is 373248, while the sum is 44.
The spelling of 64123941383 in words is "sixty-four billion, one hundred twenty-three million, nine hundred forty-one thousand, three hundred eighty-three".
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