Base | Representation |
---|---|
bin | 111011101110000101… |
… | …011011001000011111 |
3 | 20010111220111201211212 |
4 | 323232011123020133 |
5 | 2022311212111112 |
6 | 45242542335035 |
7 | 4430023336331 |
oct | 735605331037 |
9 | 203456451755 |
10 | 64123941407 |
11 | 252163252a9 |
12 | 10516b8a47b |
13 | 607bc557c6 |
14 | 316446b451 |
15 | 1a0480b522 |
hex | eee15b21f |
64123941407 has 2 divisors, whose sum is σ = 64123941408. Its totient is φ = 64123941406.
The previous prime is 64123941403. The next prime is 64123941421. The reversal of 64123941407 is 70414932146.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 64123941407 - 22 = 64123941403 is a prime.
It is a super-2 number, since 2×641239414072 (a number of 22 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (64123941403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32061970703 + 32061970704.
It is an arithmetic number, because the mean of its divisors is an integer number (32061970704).
Almost surely, 264123941407 is an apocalyptic number.
64123941407 is a deficient number, since it is larger than the sum of its proper divisors (1).
64123941407 is an equidigital number, since it uses as much as digits as its factorization.
64123941407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 41.
The spelling of 64123941407 in words is "sixty-four billion, one hundred twenty-three million, nine hundred forty-one thousand, four hundred seven".
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