Base | Representation |
---|---|
bin | 1100011100011100… |
… | …10111111101110011 |
3 | 122020121200001102121 |
4 | 12032032113331303 |
5 | 102140330201042 |
6 | 3022543055111 |
7 | 324364262041 |
oct | 61616277563 |
9 | 18217601377 |
10 | 6681100147 |
11 | 2919341477 |
12 | 13655a1497 |
13 | 82621b6c7 |
14 | 475467391 |
15 | 291825367 |
hex | 18e397f73 |
6681100147 has 4 divisors (see below), whose sum is σ = 7074106056. Its totient is φ = 6288094240.
The previous prime is 6681100141. The next prime is 6681100157. The reversal of 6681100147 is 7410011866.
6681100147 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 7410011866 = 2 ⋅3705005933.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6681100147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (6681100141) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 196502929 + ... + 196502962.
It is an arithmetic number, because the mean of its divisors is an integer number (1768526514).
Almost surely, 26681100147 is an apocalyptic number.
6681100147 is a deficient number, since it is larger than the sum of its proper divisors (393005909).
6681100147 is a wasteful number, since it uses less digits than its factorization.
6681100147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 393005908.
The product of its (nonzero) digits is 8064, while the sum is 34.
The square root of 6681100147 is about 81737.9969597983. The cubic root of 6681100147 is about 1883.4293212326.
The spelling of 6681100147 in words is "six billion, six hundred eighty-one million, one hundred thousand, one hundred forty-seven".
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