Base | Representation |
---|---|
bin | 10011111000011001110… |
… | …10110110011110001001 |
3 | 2102022020120022111000121 |
4 | 21330030322312132021 |
5 | 42143010314212441 |
6 | 1241452554303241 |
7 | 100232156622151 |
oct | 11741472663611 |
9 | 2368216274017 |
10 | 683116554121 |
11 | 243787538941 |
12 | b0486427b21 |
13 | 4c557665191 |
14 | 250c4cc5761 |
15 | 12b81c54dd1 |
hex | 9f0ceb6789 |
683116554121 has 16 divisors (see below), whose sum is σ = 724211483904. Its totient is φ = 642123465984.
The previous prime is 683116554067. The next prime is 683116554149. The reversal of 683116554121 is 121455611386.
It is a happy number.
It is a 3-Lehmer number, since φ(683116554121) divides (683116554121-1)3.
It is a cyclic number.
It is not a de Polignac number, because 683116554121 - 219 = 683116029833 is a prime.
It is a super-3 number, since 3×6831165541213 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
683116554121 is a Rhonda number in base 10.
Its product of digits (172800) is a multiple of the sum of its prime divisors (17280).
It is not an unprimeable number, because it can be changed into a prime (683116551121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 49469200 + ... + 49483006.
It is an arithmetic number, because the mean of its divisors is an integer number (45263217744).
Almost surely, 2683116554121 is an apocalyptic number.
It is an amenable number.
683116554121 is a deficient number, since it is larger than the sum of its proper divisors (41094929783).
683116554121 is a wasteful number, since it uses less digits than its factorization.
683116554121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17280.
The product of its digits is 172800, while the sum is 43.
The spelling of 683116554121 in words is "six hundred eighty-three billion, one hundred sixteen million, five hundred fifty-four thousand, one hundred twenty-one".
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